Answer by Patrick Stevens for Cardinal exponentiation question of infinite...
You have $\kappa = \sum_{\alpha < \beta} \kappa_{\alpha}$, so let $X$ be a set of cardinality $\kappa$, and $X_{\alpha}$ of cardinality $\kappa_{\alpha}$.Then $$X = \bigsqcup_{\alpha < \beta}...
View ArticleCardinal exponentiation question of infinite cardinals.
I got a little confused with a question about cardinal exponentiation:Let $\beta$ be an ordinal, and let $K_\alpha$ , $\alpha < \beta$, be infinite cardinals with $K= \sum_{\alpha<\beta}K_\alpha$...
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